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Adjacency List in a Graph

   from collections import defaultdict graph=defaultdict(list) v,e=map(int,input().split()) for i in range(e):     u,v=map(str,input().split())     graph[u].append(v)     graph[v].append(u)      for i in graph:     print(i,"->",graph[i]) Input: 7 9 A B A C A F C E C F C D D E D G G F Output: F -> ['A', 'C', 'G'] C -> ['A', 'E', 'F', 'D'] G -> ['D', 'F'] D -> ['C', 'E', 'G'] A -> ['B', 'C', 'F'] E -> ['C', 'D'] B -> ['A']       
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Repeat and Missing Number Array Asked in: Amazon

 You are given a read-only array of n integers from 1 to n.

Each integer appears exactly once except A which appears twice and B which is missing.

Return A and B.

Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

Note that in your output A should precede B.

Example:

Input:[3 1 2 5 3] 

Output:[3, 4] 

A = 3, B = 4
Solution:

class Solution:
    # @param A : tuple of integers
    # @return a list of integers
    def repeatedNumber(self, A):
        d={}
        
        for i in A:
            if i in d:
                d[i]+=1
            else:
                d[i]=1
        for i in range(1,len(A)+1):
            if i not in d:
                d[i]=0
                
        return [max(d,key=lambda x:d[x]),min(d,key=lambda x:d[x])]
        
     
        

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