Check the given number is power of 2 using BitWise

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# if a number is power of 2 then n&(n-1) results 0

#lets see n=4

#in binary 4 is 100

#in binary 3 is 011

#so bitwise & = 000 =>0


def ispowerof2(n):

    x=n 

    y=n&(n-1)

    

    print(x and not(y))

    


n=int(input())

ispowerof2(n)



 

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